MATH SOLVE

4 months ago

Q:
# Help Please!Solve for d.5+d>5−dSolve for p.2p+3>2(p−3)

Accepted Solution

A:

Solve for d.

5+d>5−d Subtract 5 from both sides of this inequality:

d>d There is no value for d that satisfies this inequality.

No value can be greater than itself.

Solve for p.

2p+3>2(p−3) Multiply this out: 2p+3>2p-6

Subtr 3 from both sides: 2p> 2p-9

This is equivalent to 2p+9>2p.

We could subtr. 2p from both sides: 0>-9.

0> -9 is always true. Thus, the given inequality has infinitely many solutions.

5+d>5−d Subtract 5 from both sides of this inequality:

d>d There is no value for d that satisfies this inequality.

No value can be greater than itself.

Solve for p.

2p+3>2(p−3) Multiply this out: 2p+3>2p-6

Subtr 3 from both sides: 2p> 2p-9

This is equivalent to 2p+9>2p.

We could subtr. 2p from both sides: 0>-9.

0> -9 is always true. Thus, the given inequality has infinitely many solutions.