point Q lies in the interior of angle RST. If m<RST=125 degrees, m<RSQ=4x-7, m<QST=11x+12, then find x.A) x=5B) x=8C) x=6D) x=4
Accepted Solution
A:
You have known that: <RST=<RSQ+<QST So we have 125°= (4x-7)+ (11x+12) and 125°= 4x-7°+ 11x+12° or 125°= 15x+5° and 15x=125°-5° and 15x=120° By dividing by 15 we have x=120°:15= 8° Have fun with x=8°